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package appl.parallel.spmd.split; |
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|
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import java.awt.Rectangle; |
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import java.awt.geom.Rectangle2D; |
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|
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import appl.parallel.spmd.split.AbstractSplitMap.NeighborhoodBoxingMode; |
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import appl.util.RasterMetaData; |
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import schmitzm.data.WritableGrid; |
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|
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/** |
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* Responsible for splitting a 2D Area (e.g a {@link WritableGrid}) in a |
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* 1D fashion, which means in this case vertical (by cols). This is only a |
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* a virtual split (a map of a split). |
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* |
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* A neighborhood range can be specified to create partitions that |
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* overlap each other. This overlapping can be done in two different |
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* ways: <br><br> |
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* |
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* <b>Inboxing</b>(default):<br><br> |
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* Inboxing means, that the neighborhood area is not part of the calculation |
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* area. |
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* <br> <br> |
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* <b>Outboxing:</b><br> |
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* Outboxing means that the neighborhood area is part of the calculation area. |
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* <br> <br> |
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* |
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* |
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* Note that this class is flexible. It may also be applied |
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* to one dimensional data structures like for example arrays. |
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* If u want to do this, simply choose one of the dimensions as 1. <br> |
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* |
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* @author Dominik Appl |
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*/ |
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|
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public class SplitMap1DVertical extends AbstractSplitMap implements SplitMap { |
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|
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|
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// public SplitMap1DVertical(SplittableResource splittable, int neighborhoodRange, int noOfPartitions, |
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// NeighborhoodBoxingMode boxingMode) { |
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// |
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// super(splittable,neighborhoodRange, noOfPartitions, boxingMode); |
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// } |
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|
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|
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public SplitMap1DVertical(int width, int height, int neighborhoodRange, int noOfPartitions, |
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NeighborhoodBoxingMode boxingMode) { |
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|
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super(width,height,neighborhoodRange, noOfPartitions, boxingMode); |
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} |
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|
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|
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/** |
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* needed for serialization |
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*/ |
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public SplitMap1DVertical(){ |
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|
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} |
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|
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/* (non-Javadoc) |
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* @see appl.parallel.spmd.split.DataSplitter#getDescription() |
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*/ |
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public String getDescription() { |
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return "1D-GridSplitter"; |
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} |
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|
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/* (non-Javadoc) |
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* @see appl.parallel.spmd.split.DataSplitter#split(appl.parallel.spmd.split.SplittableRessource) |
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*/ |
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public void makeMap() { |
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//the local calculation area is partitioned |
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int nextUpperLeftCorner = (int) globalBounds.getX(); //next x-value (will be 0) |
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for (int i = 0; i < noOfPartitions; i++) { |
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|
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//calculate length based on weights |
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int pWidth = (int) (globalBounds.getWidth() * weights[i]); |
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|
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//for the last position make sure, that ALL data is used |
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//and no line is lost due to rounding errors in weight calculation |
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if(i==noOfPartitions-1) |
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pWidth = (int) globalBounds.getWidth() - nextUpperLeftCorner; |
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|
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//create inboxing(!) partition |
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partitionCalculationBounds[i] = new Rectangle( |
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nextUpperLeftCorner, (int) globalBounds.getY(), pWidth, |
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(int) globalBounds.getHeight()); |
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|
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//if there is only one partition there are no explicit neighborhood bounds |
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if(noOfPartitions==1) |
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partitionNeighborhoodBounds[i]=partitionCalculationBounds[i]; |
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//else simply calculate the neighborhood bounds out of the previosly |
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//created calculation Area |
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else |
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partitionNeighborhoodBounds[i] = new Rectangle( |
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(int)partitionCalculationBounds[i].getX() - neighborhoodRange, |
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(int) globalBounds.getY(), |
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(int)(partitionCalculationBounds[i].getWidth() + 2 * neighborhoodRange), |
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(int)(partitionCalculationBounds[i].getHeight())); |
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|
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//the first and the last partition have a neighborhood area only on one side of |
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//the calculation area: |
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partitionNeighborhoodBounds[i] = partitionNeighborhoodBounds[i].intersection(globalBounds); |
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nextUpperLeftCorner += pWidth; //+1 not required - the partitions will not overlap |
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|
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//the partitionCalculation bounds were created for inboxing: |
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if(boxingMode==NeighborhoodBoxingMode.outBoxing) |
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partitionCalculationBounds[i]=partitionNeighborhoodBounds[i]; |
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|
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} |
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} |
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|
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/* (non-Javadoc) |
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* @see appl.parallel.spmd.split.SplitMap#getNeighborsForPosition(int) |
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*/ |
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public int[] getNeighborsForPosition(int pos) { |
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int[] oneReturn = new int[1]; |
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int[] twoReturns = new int[2]; |
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|
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//this is very simple in one 1D case, of course: |
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//if only one Partition return null |
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if (noOfPartitions == 1) |
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return new int[0]; |
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|
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//for first partition |
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if ((pos == 0)) { |
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oneReturn[0] = 1; |
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return oneReturn; |
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} |
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//for last partition |
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if (pos == noOfPartitions - 1) { |
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oneReturn[0] = noOfPartitions - 2; |
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return oneReturn; |
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} |
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//for every other partition |
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twoReturns[0] = pos - 1; |
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twoReturns[1] = pos + 1; |
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return twoReturns; |
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} |
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|
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} |